21. 3 Sum

Given an integer array nums. Return all triplets such that:

  • i != j, i != k, and j != k
  • nums[i] + nums[j] + nums[k] == 0.

Notice that the solution set must not contain duplicate triplets. One element can be a part of multiple triplets. The output and the triplets can be returned in any order.

Example 1:

Input: nums = [2, -2, 0, 3, -3, 5]

Output: [[-2, 0, 2], [-3, -2, 5], [-3, 0, 3]]

Explanation:

nums[1] + nums[2] + nums[0] = 0

nums[4] + nums[1] + nums[5] = 0

nums[4] + nums[2] + nums[3] = 0

Example 2:

Input: nums = [2, -1, -1, 3, -1]

Output: [[-1, -1, 2]]

Explanation:

nums[1] + nums[2] + nums[0] = 0

Note that we have used two -1s as they are separate elements with different indexes

But we have not used the -1 at index 4 as that would create a duplicate triplet

Now Your Turn!

Pick the correct output for the given input

Input: nums = [8, -6, 5, 4]

(Give answer with the output and triplets sorted in ascending order)

Still unsure what the problem is asking ?

Let’s go through a few more examples, step by step, to make it clearer.

Constraints:

  • 1 <= nums.length <= 3000
  • -104 <= nums[i] <= 104

Hints

Frequently Occurring Doubts

Interview Follow-up Questions

0
class Solution {
public:
vector<vector<int>> threeSum(vector<int>& nums) {
}
};
Test Case

Input:

Nums