**Problem Statement:** Given an integer **N, **print the following pattern :

Here, N = 5.

**Examples**:

Input Format: N = 3Result: 1 2 3 4 5 6Input Format: N = 6Result: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21

**Solution**

** Disclaimer**:

*Don’t jump directly to the solution, try it out yourself first.*

**Approach**:

There are 4 general rules for solving a pattern-based question :

- We always use nested loops for printing the patterns. For the outer loop, we count the number of lines/rows and loop for them.
- Next, for the inner loop, we focus on the number of columns and somehow connect them to the rows by forming a logic such that for each row we get the required number of columns to be printed.
- We print the numbers inside the inner loop.
- Observe symmetry in the pattern or check if a pattern is a combination of two or more similar patterns or not.

In this problem, we just have to print the right-angled number pyramid but here, we also have to increase the number each time we print it. For printing, the right-angled pyramid as we know the outer loop runs for N times and the inner loop runs for i times. Now, to print an increasing number pyramid we just have to increment the number inside the inner loop so that after printing the number each time it increases by 1.

**Code**:

## C++ Code

```
#include <bits/stdc++.h>
using namespace std;
void pattern13(int N)
{
// starting number
int num =1;
// Outer loop for the number of rows.
for(int i=1;i<=N;i++){
// Inner loop will loop for i times and
// print numbers increasing by 1 each time.
for(int j=1;j<=i;j++){
cout<<num<<" ";
num =num+1;
}
// As soon as the numbers for each iteration are printed, we move to the
// next row and give a line break otherwise all numbers
// would get printed in 1 line.
cout<<endl;
}
}
int main()
{
// Here, we have taken the value of N as 5.
// We can also take input from the user.
int N = 5;
pattern13(N);
return 0;
}
```

**Output **

1

2 3

4 5 6

7 8 9 10

11 12 13 14 15

## Java Code

```
class Main {
static void pattern13(int N)
{
// starting number.
int num =1;
// Outer loop for the number of rows.
for(int i=1;i<=N;i++){
// Inner loop will loop for i times and
// print numbers increasing by 1 each time.
for(int j=1;j<=i;j++){
System.out.print(num + " ");
num =num+1;
}
// As soon as the numbers for each iteration are printed, we move to the
// next row and give a line break otherwise all numbers
// would get printed in 1 line.
System.out.println();
}
}
public static void main(String[] args) {
// Here, we have taken the value of N as 5.
// We can also take input from the user.
int N = 5;
pattern13(N);
}
}
```

**Output **

1

2 3

4 5 6

7 8 9 10

11 12 13 14 15

Special thanks toplease check out this article.Priyanshi Goelfor contributing to this article on takeUforward. If you also wish to share your knowledge with the takeUforward fam,If you want to suggest any improvement/correction in this article please mail us at [email protected]