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class Solution:
    # Function to print a square pattern of stars
    def pattern1(self, N):
        # Outer loop to handle rows
        for i in range(N):
            # Inner loop to handle columns for each row
            for j in range(N):
                # Print a star followed by a space
                print("*", end=" ")
            # After printing stars in a row, move to the next line
            print() 

# Driver code
sol = Solution()
N = 5  # Set the size of the square (5x5)
sol.pattern1(N)  # Call the function to print the pattern

12345678910111213141516171819202122

class Solution {
    // Function to print a square pattern of stars
    pattern1(N) {
        // Outer loop to handle rows
        for (let i = 0; i < N; i++) {
            let row = ""; // Initialize an empty string for the row
            // Inner loop to handle columns for each row
            for (let j = 0; j < N; j++) {
                // Add a star followed by a space to the row string
                row += "* "; 
            }
            // Print the complete row
            console.log(row); 
        }
    }
}

// Driver code
const sol = new Solution();
const N = 5; // Set the size of the square (5x5)
sol.pattern1(N); // Call the function to print the pattern

Complexity Analysis

Time Complexity: O(N²), since we print N stars for each of the N rows.

Space Complexity: O(1), no additional space is used apart from loop variables.