Algorithm

Create a visited array for array B, initialized with 0 to indicate that initially none of the elements in array B are visited.
Start iterating through array A and for each element, check if it matches with any element in array B that hasn't been visited yet.
If a match is found, mark the corresponding element in array B as visited, add the element to the answer array, and proceed to the next element in array A.
If a match is found but the element in array B has already been visited, skip adding it to the answer array, as it has been mapped to another element already.
Continue iterating through array A until all elements are processed, and the final intersection will be stored in the answer array.

Code

#include <bits/stdc++.h>
using namespace std;

// compute intersection with multiplicity using visited flags on B
vector<int> intersectionOfArrays(vector<int> A, vector<int> B) {
  // answer container
  vector<int> ans;
  // visited flags for B to avoid reusing elements
  vector<int> visited(B.size(), 0);

  // iterate A
  for (size_t i = 0; i < A.size(); i++) {
    // iterate B
    for (size_t j = 0; j < B.size(); j++) {
     