**Problem Statement: **Write a program to count the number of words in a given string.

**Examples:**

** Disclaimer**:

*Don’t jump directly to the solution, try it out yourself first.*

**Solution:**

**Intuition:**

A string is a stream of characters. A word in a string is a bunch of characters surrounded by spaces on both sides or space on one side and string start/end on the other. In case a string is a single word, there will be no space around the word.

Now, we can see by the observation that the number of words will always be (number of spaces + 1). To understand this, think of a log of wood. To get three pieces out of a single log, we need to make two cuts to the log. Here spaces are just like cuts, if there are 2 cuts, we get 3 pieces, similarly, if we have 2 spaces we have 3 words. Hence for ‘n’ spaces, the number of words will be ‘n+1’.

Now we apply this formula to get the answer.

**Approach: **

The algorithm steps are stated below:

- Iterate over the string and count the number of spaces and store it in a variable ( say spaces).
- Return the answer as (spaces + 1)

**Code:**

## C++ Code

```
#include <bits/stdc++.h>
using namespace std;
int main() {
string str = "HI AMY AND JAY";
int n = str.length();
int spaces=0;
for(int i=0; i<n; i++){
if(str[i]==' ')
spaces= spaces+1;
}
cout<<"The number of words are "<< spaces+1;
}
```

**Output:** The number of words is 4

**Time Complexity: O(N)**

Reason: We iterate for the length of the string

**Space Complexity: O(1)**

Reason: We are not using any extra space.

## Java Code

```
import java.io.*;
import java.util.*;
class takeuforward {
// Driver code
public static void main(String[] args) {
String str = "HI AMY AND JAY";
int n = str.length();
int spaces = 0;
for (int i = 0; i < n; i++) {
if (str.charAt(i) == ' ')
spaces = spaces + 1;
}
System.out.print("Number of words are ");
System.out.print(spaces + 1);
}
}
```

**Output:** The number of words is 4

**Time Complexity: O(N)**

Reason: We iterate for the length of the string

**Space Complexity: O(1)**

Reason: We are not using any extra space.

Special thanks toplease check out this articleAnshuman Sharmafor contributing to this article on takeUforward. If you also wish to share your knowledge with the takeUforward fam,