Take a variable ans to store final answer.Initially let the value of ans be 1.
Multiply ans with x for n times.
Print ans.
Code
                                                            
#include<bits/stdc++.h>
using namespace std;
class Solution{
int main()
{
    int x= 5, n = 3;
    int ans = 1;
    for (int i = 0; i < n; i++) {
        ans = ans * x; //Simply multiply the ans with x
    }
    cout <<x<<" raised to the power "<<n<<" is "<< ans;
}
                                
                            
                        

                                                            
public class Main {
    public static void main(String[] args) {
        int x = 5, n = 3;
        int ans = 1;
        for (int i = 0; i < n; i++) {
            ans = ans * x;  //Simply multiply the ans with x
        }
        System.out.println(x + " raised to the power " + n + " is " + ans);
    }
}
                                
                            
                        

                                                            
def main():
    x = 5
    n = 3
    ans = 1
    for i in range(n):
        ans *= x  //Simply multiply the ans with x
    print(f"{x} raised to the power {n} is {ans}")

if __name__ == "__main__":
    main()
                      