# Greatest of three numbers

Problem Statement: Given three numbers. Find the greatest of three numbers.

Examples:

```Example 1:
Input: 1 3 5
Output: 5
Explanation: Answer is 5.Since 5 is greater than 1 and 3.

Example 2:
Input: 1.123  1.124 1.125
Output: 1.125
Explanation: Answer is 1.125. Since 1.125 is greater than 1.123 and 1.124```

### Solution

Disclaimer: Don’t jump directly to the solution, try it out yourself first.

Solution 1: Using max()(C++)/ Math max()(Java)

Approach: Standard Library function

Synatax for C++: max({num1,num2,num3}) or max(num1,max(num1,num2))

Syntax for Java: Math.max(num1,Math.max(num2.num3))

Code:

## C++ Code

``````#include<bits/stdc++.h>
using namespace std;
int main() {
double num1 = 1, num2 = 3, num3 = 5;
cout << "The maximum of the three numbers is "<<max(num1, (num2, num3));
}
``````

Output:

The maximum of the three numbers is 5

Time Complexity: O(1).

Space Complexity: O(1)

## Java Code

``````public class Main {
public static void main(String args[]) {
double num1 = 1.123, num2 = 1.124, num3 = 1.125;
System.out.println("The greatest of the three numbers is "+Math.max(num1, Math.max(num2, num3)));
}
}
``````

Output:

The greatest of the three numbers is 1.125

Time Complexity: O(1).

Space Complexity: O(1).

Solution 2: Using if-else statements

Approach:

• If num1 is greater than num2 and num3 then print num1.
• If num2 is greater than num3 and num1 then print num2.
• Else print num3.

Code:

## C++ Code

``````#include<bits/stdc++.h>
using namespace std;
int main() {
double num1 = 1, num2 = 3, num3 = 5;
if (num1 > num2 && num1 > num3) {
cout <<"The greatest of the three numbers is "<< num1;
}
else if (num2 > num1 && num2 > num3) {
cout <<"The greatest of the three numbers is "<< num2;
}
else {
cout <<"The greatest of the three numbers is "<< num3;
}
}
``````

Output:

The greatest of the three numbers is 5

Time Complexity: O(1).

Space Complexity: O(1).

## Java Code

``````public class Main {
public static void main(String args[]) {
double num1 = 1.123, num2 = 1.124, num3 = 1.125;
if (num1 > num2 && num1 > num3) {
System.out.println("The greatest of the three numbers is "+num1);
} else if (num2 > num1 && num2 > num3) {
System.out.println("The greatest of the three numbers is "+num2);
} else {
System.out.println("The greatest of the three numbers is "+num3);
}
}
}
``````

Output:

The greatest of the three numbers is 1.125

Time Complexity: O(1).

Space Complexity: O(1).